Dealer: East
Vul: E-W
T842 |
642 |
AK62 |
A6 |
AQJ95 |
A8 |
93 |
KT82 |
| South | West | North | East |
|---|---|---|---|
| - | - | - | 1![]() |
1![]() | Pass | 2![]() | Pass |
3![]() | Pass | 3![]() | Pass |
3![]() | Pass | 4![]() | Pass |
5![]() | Pass | 6![]() | Pass |
| Pass | Pass |
3 and you let East’s
J hold the trick. East returns the
K to your ace. Obviously, East will have the
K. If it is singleton or doubleton, there will be 12 fairly easy tricks. What is your plan for overcoming the cases where he has three or four trumps to the king?
Solution
Suppose this is the full deal:
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Dealer: South
Vul: Both
A864 |
T95 |
K86 |
Q54 |
KQ92 |
K |
T74 |
KT972 |
| South | West | North | East |
|---|---|---|---|
| Pass | 1![]() | Pass | 2![]() |
2![]() | 4![]() | 4![]() | X |
| Pass | Pass | Pass |
CLICK ON LINK: http://web2.acbl.org/tournaments/results/2013/04/1304090.htm
--------------------------------
OR GO UNDER "TOURNAMENT RESULTS" AND CLICK ON 2013 UNDER "NORTH BAY SECTIONAL"
Dealer: South
Vul: Both
53 |
7532 |
KQJT |
Q42 |
AK9862 |
AKQT |
A |
A5 |
| South | West | North | East |
|---|---|---|---|
2![]() | Pass | 2![]() | Pass |
2![]() | Pass | 3![]() | Pass |
3![]() | Pass | 4![]() | Pass |
7![]() | Pass | Pass | Pass |
J to your ace?
Solution
If spades and trumps are 3-2, it will be easy to make 13 tricks. The best plan is to draw two rounds of trumps then cash the
A and
K. When all follow to the spades, draw the last trump, cash the
A and ruff a spade. After throwing your remaining club on a good diamond, your hand will be high.
Dealer: West
Vul: E-W
T976 |
AQ2 |
KJ54 |
Q3 |
5 |
KJ63 |
AQT6 |
AT75 |
| South | West | North | East |
|---|---|---|---|
| - | Pass | 1![]() | Pass |
1![]() | 1![]() | X | Pass |
4![]() | Pass | Pass | Pass |
Solution
Dealer: North
Vul: E-W
T862 |
AQJ76 |
QJT |
A |
AKJ4 |
K42 |
A95 |
762 |
Q. How do you plan to make 12 tricks?
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Dealer: East
Vul: E-W
QJ6 |
6 |
AJ983 |
QJ75 |
KT984 |
Q875 |
2 |
AK9 |
| South | West | North | East |
|---|---|---|---|
| - | - | - | 1![]() |
1![]() | X | 2![]() | Pass |
2![]() | Pass | 4![]() | Pass |
| Pass | Pass |
bid showed at least four diamonds unless precisely 4=4=3=2 shape. West’s double was negative. North’s cuebid showed a sound raise in spades. You were uncertain about the final spot, so you made a trial bid in hearts, prompting North to leap directly to game. How do you plan to make 10 tricks after West leads the
A and another spade?
Solution
Dealer: West
Vul: E-W
964 |
A62 |
A84 |
8643 |
K853 |
K73 |
KQ5 |
AQ5 |
| South | West | North | East |
|---|---|---|---|
| - | 2![]() | Pass | Pass |
| 2NT | Pass | 3NT | Pass |
| Pass | Pass |
opener showed 6-9 high-card points, leads the
Q. As expected, East has to discard and he chooses a heart. Is there any way to make nine tricks against the best defense? A second question: How would you play 3NT if West had led the
10?You need East to have begun with three clubs headed by the king and jack. At trick two, you should cash the
A. Suppose this is the full deal:
Dealer: West
Vul: N-S
QT652 |
A764 |
T952 |
![]() |
KJ987 |
93 |
6 |
AT973 |
| South | West | North | East |
|---|---|---|---|
| - | 1![]() | Pass | 1![]() |
1![]() | 2![]() | 4![]() | X |
| Pass | Pass | Pass |
K, shifting to the
5 at trick two. Is there any chance of making 10 tricks?
Solution
The first question that you should ask is “Why didn’t West shift to a trump at trick two?” The obvious answer is that he doesn’t have one. You have to suppose the full deal is similar to this one:
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Dealer: South
Vul: Both
AQ652 |
KJT6 |
K |
J53 |
3 |
AQ97 |
AJ842 |
AK4 |
| South | West | North | East |
|---|---|---|---|
1![]() | Pass | 1![]() | Pass |
2![]() | Pass | 3 1 | Pass |
4![]() | Pass | 4NT | Pass |
5 2 | Pass | 5![]() | Pass |
6 3 | Pass | 6![]() | Pass |
6![]() | Pass | Pass | Pass |
.
Q plus
K.
West leads the
9, taken by dummy’s ace. East follows with an encouraging signal. Assuming that neither defender has a singleton in a minor suit, what is the safest line to make 12 tricks?
Solution
Suppose the full deal is as follows:
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8 or
5.
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